A particle of mass `0.6g` and having charge of `25 nC` is moving horizontally with a uniform velocity `1.2xx10^(4)ms^(-1)` in a uniform magnetic field, then the value of the magnetic induction is `(g=10ms^(-2))`

Options

A. Zero
B. `10T`
C. `20T`
D. `200T`

Answer

C

Explanation

Particle will move with uniform velocity when its acceleration is zero.

i.e., `|F_(m)|=mgimpliesmg=qvB`
` implies B= (mg)/(qv)=(0.6xx10^(-3)xx10)/(25xx10^(-9)xx1.2xx10^(4))= 20T`