Home
Class 12
PHYSICS
A particle of mass 0.6g and having charg...

A particle of mass `0.6g` and having charge of `25 nC` is moving horizontally with a uniform velocity `1.2xx10^(4)ms^(-1)` in a uniform magnetic field, then the value of the magnetic induction is `(g=10ms^(-2))`

A

Zero

B

`10T`

C

`20T`

D

`200T`

Text Solution

Verified by Experts

The correct Answer is:
C
Particle will move with uniform velocity when its acceleration is zero.

i.e., `|F_(m)|=mgimpliesmg=qvB`
` implies B= (mg)/(qv)=(0.6xx10^(-3)xx10)/(25xx10^(-9)xx1.2xx10^(4))= 20T`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOURCE AND EFFECT OF MAGNETIC FIELD

    A2Z|Exercise Force On A Current Carrying Conductor In Magnetic Field|42 Videos

  • SOURCE AND EFFECT OF MAGNETIC FIELD

    A2Z|Exercise Magnetic Dipole|32 Videos

  • SEMICONDUCTOR ELECTRONICS

    A2Z|Exercise EXERCISE|29 Videos

  • WAVE OPTICS

    A2Z|Exercise Section D - Chapter End Test|29 Videos

Similar Questions

Explore conceptually related problems

An electron is moving northwards with a velocity 3*0xx10^7ms^-1 in a uniform magnetic field of 10T directed eastwards. Find the magnitude and direction of the magnetic force on the electron. (e=1*6xx10^(-19)C)

A charged particle of charge 1 mC and mass 2g is moving with a speed of 5m/s in a uniform magnetic field of 0.5 tesla. Find the maximum acceleration of the charged particle

Knowledge Check

  • A particle of mass 2 kg chrge 1 mC is projected vertially with velocity k 10 ms^-1 . There is as uniform horizontal electric field of 10^4N//C, then

    A
    the horizontal range of the particle is `10 m`
    B
    the time of flight of the particle is `2s`
    C
    the maximum heighty reached is `5m`
    D
    the horizontal range of the particle is `5m`

  • A particle of mass 0.5 gm and charge 2.5xx10^(-8) coulomb is moving with velocity 6xx10^(4)m//s , horizontally what should be the value of magnetic field acting on it so that the particle is able to move in a straight line - (g=9.8m//s^(2))

    A
    `0.327" Weber"//m^(2)`
    B
    `3.27" Weber"//m^(2)`
    C
    `32.7"Weber"//m^(2)`
    D
    this is not possible

  • A charge particle moves with velocity vec(V) in a uniform magnetic field vec(B) . The magnetic force experienced by the particle is

    A
    always zero
    B
    zero, if `vec(B) and vec(V)` are perpendicualr
    C
    zero, if `vec(B) and vec(V)` are parallel
    D
    zero, if `vec(B) and vec(V)` are inclined at `45^(@)`

    • Similar Questions

    Explore conceptually related problems

    A charge q moves with a velocity 2 ms^(-1) along x-axis in a uniform magnetic field vec B = (hat i + 2 hat j + 3 hat k ) then charge will experience a force

    A proton enters a magnetic field with a velocity of 2.5 xx10^(7)ms^(-1) making an angle 30^(@) with the magnetic field. The force on the proton is (B=25T)

    A particle of mass 1 mg has the same wavelength as an electron moving with a velocity of 3 xx 10^(6) ms^(-1) . The velocity of the particle is

    A charged particle moves with a velocity vecv in a uniform magnetic field vecB . The magnetic force experienced by the particle is

    A charged particle moves with velocity v in a uniform magnetic field vecB . The magnetic force experienced by the particle is

    Home
    Profile