If a change in current of `0.01 A` in one coil produces change in magnetic flux of `1.2xx10^(-2)Wb` in the other coil, then the mutual inductance of the two coils in henry

Options

A. `0`
B. `0.5`
C. `1.2`
D. `3`

Explanation

To find the mutual inductance \( M \) of the two coils, we can use the formula:

\[ M = \frac{\Delta \Phi}{\Delta I} \]

where:
- \( \Delta \Phi \) is the change in magnetic flux (in Weber),
- \( \Delta I \) is the change in current (in Ampere).

Given:
- \( \Delta \Phi = 1.2 \times 10^{-2} \, \text{Wb} \)
- \( \Delta I = 0.01 \, \text{A} \)

Now, we can substitute these values into the formula:

\[ M = \frac{1.2 \times 10^{-2} \, \text{Wb}}{0.01 \, \text{A}} \]

Calculating the mutual inductance:

\[ M = \frac{1.2 \times 10^{-2}}{0.01} \]

\[ M = 1.2 \times 10^{0} \, \text{H} \]

\[ M = 1.2 \, \text{H} \]

Thus, the mutual inductance of the two coils is \( 1.2 \, \text{H} \).