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Angular width (beta) of central maximum ...

Angular width `(beta)` of central maximum of a diffraction pattern on a single slit does not depend upon

A

(a) Distance between slit and source

B

(b) Wavelength of the slit

C

(c) Width of the slit

D

(d) Frequency of light used

Text Solution

Verified by Experts

The correct Answer is:
A
For single slit diffraction pattern `d sin theta=lambda(d=slit wi dth)`
Angular width `=2theta=2sin^-1(lambda/d)`
It is independent of D, i.e., distance between screen and slit.
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Knowledge Check

  • The angular width of the central maximum of the diffraction patternn in a single slit (of width a) experiment, with lamda as the wavelenth of light, is

    A
    `(3lamda)/(2a)`
    B
    `(lamda)/(2a)`
    C
    `(2lamda)/(a)`
    D
    `(lamda)/(a)`

  • Angular width of central maxima of a single slit diffraction pattern is independent of

    A
    slit width
    B
    frequency of the light used
    C
    wavelength of the light used
    D
    distance between slit and screen

  • Central fringe obtained in diffraction pattern due to a single slit-

    A
    is of minimum intensity
    B
    is of maximum intensity
    C
    intensity does not depend upon slit width
    D
    none of the above

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