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N2O4 is dissociated to 33% and 40% at to...

`N_2O_4` is dissociated to `33%` and `40%` at total pressure `P_1 and P_2` atm respectively. Then the ratio `P_(1)//P_(2)` is

A

`7//4`

B

`7//3`

C

`8//3`

D

`8//5`

Text Solution

Verified by Experts

`underset(1-alpha)underset(2)(N_(2)O_(4))hArrunderset(2alpha)underset(0)(2NO_(2))`
`K_(p)=((n_(NO_(2)))^(2))/((n_(N_(2)O_(4))))xx[(P)/(sumn)]^(1)`
For `33%` dissociation:
`K_(p)=((2xx33)^(2))/(67)xx[(P_(1))/(133)]^(1)`
For `50%` dissociation:
`K_(p)=((2xx50)^(2))/(50)xx[(P_(2))/(150)]^(1)`
`:. (P_(1))/(P_(2))=(133xx67xx(2xx50)^(2))/((2xx33)^(2)xx150xx50)=2.72`
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Knowledge Check

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