Specific heat of argon at constant pressure is `0.125 cal.g^(-1) K^(-1)`, and at constant volume `0.075 cal.g^(-1)K^(-1)`. Calculate the density of argon at N.T.P. Given `J = 4.18 xx 10^(7)" erg "cal^(-1)` and normal pressure = `1.01 xx 10^(6)" dyne "cm^(-2)`.

Explanation

To calculate the density of argon at Normal Temperature and Pressure (N.T.P), we will follow these steps:

### Step 1: Write down the given data
- Specific heat at constant pressure, \( C_P = 0.125 \, \text{cal/g/K} \)
- Specific heat at constant volume, \( C_V = 0.075 \, \text{cal/g/K} \)
- Conversion factor, \( J = 4.18 \times 10^7 \, \text{erg/cal} \)
- Normal pressure, \( P = 1.01 \times 10^6 \, \text{dyne/cm}^2 \)
- Temperature at N.T.P, \( T = 273 \, \text{K} \)
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