A particle executing SHM along a straight line has a velocity of `4ms^(-1)`, and at a distance of 3m from its mean position and `3ms^(-1)`, when at a distance of 4m from it. Find the time it take to travel 2.5m from the positive extremity of its oscillation.

Explanation

To solve the problem, we will use the properties of Simple Harmonic Motion (SHM). We know that the velocity of a particle in SHM can be expressed in terms of its displacement from the mean position and the amplitude of the motion.

### Step 1: Understand the given information
We have two conditions:
1. At a distance \( x_1 = 3 \, \text{m} \) from the mean position, the velocity \( v_1 = 4 \, \text{m/s} \).
2. At a distance \( x_2 = 4 \, \text{m} \) from the mean position, the velocity \( v_2 = 3 \, \text{m/s} \).

### Step 2: Use the formula for velocity in SHM
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