Give expression for average value of a.c. voltage `V = V_(0) sin omega t` over interval `t = 0` to `t = (pi)/(omega)`

Explanation

To find the average value of the alternating current (a.c.) voltage given by the equation \( V = V_0 \sin(\omega t) \) over the interval from \( t = 0 \) to \( t = \frac{\pi}{\omega} \), we can follow these steps:

### Step 1: Understand the Function
The given voltage function is \( V(t) = V_0 \sin(\omega t) \). This is a sinusoidal function, where \( V_0 \) is the peak voltage and \( \omega \) is the angular frequency.

### Step 2: Identify the Interval
We need to calculate the average value of this function over the interval from \( t = 0 \) to \( t = \frac{\pi}{\omega} \). This interval represents half of the time period of the sinusoidal function, since the time period \( T \) is given by \( T = \frac{2\pi}{\omega} \).

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