Home
Class 12
PHYSICS
Uranium ""(92)U^(238) is not suitable fo...

Uranium `""_(92)U^(238)` is not suitable for chain reaction . Why ?

Text Solution

Verified by Experts

This is because only fast moving neutrons of 12 MeV energy can cause fission of `._92U^(238)` nuclei. Such neutrons have chance of interaction. They escape the fissionable material without causing fission.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ATOMS AND NUCLEI

    PRADEEP|Exercise (III) Questions short 21|1 Videos

  • ATOMS AND NUCLEI

    PRADEEP|Exercise (III) Questions short 22|1 Videos

  • ATOMS AND NUCLEI

    PRADEEP|Exercise (II) Questions short 18|1 Videos

  • COMMUNICATION SYSTEMS

    PRADEEP|Exercise MODEL TEST PAPER-2|9 Videos

Similar Questions

Explore conceptually related problems

Define nuclear fission. Write the fission reaction of a neutron with uranium isotope ""_(92)U^(235) . Write one use of nuclear fission reaction.

Show that ""_(92)^(238)U cannot spontaneosly emit a proton. Given : ""_(92)^(238)U=238.05079u, ""_(91)^(237)Pa=237.05121u, ""_(1)^(1)H=1.00783u

Knowledge Check

  • Uranium ._(92)U^(235) on bombardment with slow neutrons produces

    A
    Deutrons
    B
    Fusion reaction
    C
    Fission reaction
    D
    Endothermic reaction

  • A uranium nucleus ._(92)U^(238) emits and alpha -particle and a beta -particle in succession. The atomic number and mass number of the final nucleus will be

    A
    90 and 233
    B
    90 and 238
    C
    91 and 238
    D
    91 and 234

  • The isotoic mass of ""_(92)^(238)U is 238.125 a.m.u. Its packing fraction is

    A
    5.25
    B
    0.125
    C
    12.5
    D
    1.25

    • Similar Questions

    Explore conceptually related problems

    Show that ""_(92)^(238)U can not spontaneously emit a proton. Given: ""_(92)^(238)U = 238.05079u, ""_(91)^(237)Pa = 237.05121u ""_(1)^(1)H = 1.00783u

    The atomic mass of uranium ._(92)^(238)U is 23.058 u , that of throium ._(90)^(234)Th is 234.0436 u and that of an alpha particle ._2^4He is 4.006 u , Determine the energy released when alpha-decay converts ._(92)^(238)U into ._(92)^(238) U . int ._(90)^(234)Th .

    Uranium ( ""_(92)U""^(238) ) decayed to ""_(82)Pb""^(206) . The process is ""_(92)U""^(238)underset(xalpha,ybeta)to.""_(82)Pb""^(206) t""_(1//2)of U""^(238)=4.5xx10""^(9) years x and y in above decay series are

    Uranium ( ""_(92)U""^(238) ) decayed to ""_(82)Pb""^(206) . The process is ""_(92)U""^(238)underset(xalpha,ybeta)to.""_(82)Pb""^(206) t""_(1//2)of U""^(238)=4.5xx10""^(9) years The analysis of a rock shows the relative number of U""^(238) and Pb""^(206) atoms (Pb/U=0.25). The age of rock will be

    Uranium ( ""_(92)U""^(238) ) decayed to ""_(82)Pb""^(206) . The process is ""_(92)U""^(238)underset(xalpha,ybeta)to.""_(82)Pb""^(206) t""_(1//2)of U""^(238)=4.5xx10""^(9) years A sample of rock from South America contains equal number of atoms of U""^(238) and Pb""^(""^(206) . The age of the rock will be

    Home
    Profile