Home
Class 12
PHYSICS
Deduce the expression, N=N(0e)^(-lambdat...

Deduce the expression, `N=N_(0e)^(-lambdat)`, for the law of radioactive decay.

Answer

Step by step text solution for Deduce the expression, N=N_(0e)^(-lambdat), for the law of radioactive decay. by PHYSICS experts to help you in doubts & scoring excellent marks in Class 12 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ATOMS AND NUCLEI

    PRADEEP|Exercise Questions Long 12|1 Videos
  • ATOMS AND NUCLEI

    PRADEEP|Exercise Questions Long 13|1 Videos
  • ATOMS AND NUCLEI

    PRADEEP|Exercise Questions Long 10|1 Videos
  • COMMUNICATION SYSTEMS

    PRADEEP|Exercise MODEL TEST PAPER-2|9 Videos

Similar Questions

Explore conceptually related problems

(a) Deduce the expression, N= N_(0) e^(-lambdat) for the law of radioactive decay. (b) (i) Write symbolically the process expressing the beta^(+) decay of " "_(11)^(22)Na . Also write the basic nuclear process underlying this decay. (ii) Is the nucleus formed in the decay of the nucleus " "_(11)^(22)Na , an isotope or isobar ?

Deduce the expression, N=N_(0)^(-lambdat) for the law of radioactive decay. (b) Is the nucleus formed in the decay of the nucleus ._(11)^(12)Na , an isotope or isobar?

Knowledge Check

  • Radioactive decay follows first-order kinetic. The mean life and half-life of nuclear decay process are tau = 1// lambda and t_(1//2) = 0.693//lambda . Therefore are a number of radioactive elements in nature, their abundance is directly proportional to half life. The amount remaining after n half lives of radioactive elements can be calculated using the relation: N = N_(0) ((1)/(2))^(n) The rate of radioactive decay is

    A
    Independent of lime
    B
    Independent of temperature
    C
    Dependent on catalyst
    D
    Dependent on the amount of elementsd not yet decayed
  • The mathematical equation of law of radioactive decay is

    A
    `N=N_(0) e^(-lambda t)`
    B
    `N=e^(-lambda t)`
    C
    `N=N_(0) e^(lambda t)`
    D
    `N_(0) =N e^(-lambda t)`
  • Radioactive disintergation always follow I order kinetics and is independent of all external factors and is represented by the relation N = N_(0) e^(-lambda t) where lambda is decay constant and N atoms are left at time t . The radioactive nature of element is expressed in terms of average life numerically equal to decay constant (1//lambda) however all the radioactive do not lose their radioactive nature in thier average life. The radioactive emission involves alpha, beta particles as well as gamma- rays.The penertrating power order is alpha lt beta lt gamma . The emissions can perntrate even thick steel walls but are however unable to penttrate Pb blocks. The S unit fo rate of decay is dps . The percentage of atoms decayed in average life of a radioactive element is:

    A
    `36.78%`
    B
    `63.22%`
    C
    `3.678%`
    D
    `6.322%`
  • Similar Questions

    Explore conceptually related problems

    Radioactive Decay Law

    Derive the relation N_(t) =N_(0)e^(-lambdat) for radioactive decay. Obtain the relation between disintegration constant and half-life.

    What is radioactivity ? Derive an experssion N=N_(0)e^(-lambda t) for radioactive disintegration.

    Expand the following N=N_(0)e^(-lambdat)

    Stability Curve and Laws of Radioactive Decay