For he ground state , the electron int e...

For he ground state , the electron int eh H-atom has an angular momentum `=h`, accord-ing to the simple Bohr model. Angular momentum is a vector ans hence there will be infi-nitely many orbits with the vector pointing in alll possible direction . In actuality , this is not true,

because Bohr model gives incorrect values of angular momentum

because only one of these would have a minimum energy

angular momentum must be in the direction of spin of electron

because electrons go around only in horizontal orbits

Text Solution

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The correct Answer is:

Simple Bohr model, infact does not give correct values of angular momentum of revolving electrons. It gives only the magnitude of angular momentum, which is a vector. So the given statement in the question is not true. Choice (a) is correct.

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Permissible value of orbit angular momentum of electron in a H-like atom will be

`1.5((h)/(pi))`

`(h)/(4pi)`

`(h)/(1.5pi)`

`(h)/(3pi)`

The angular momentum of the electron in the third orbit of H atom is

`2.3 xx10^(-34) Js`

`3.2 xx10^(-34) Js`

`5.2 xx10^(-34) Js`

`4.2xx10^(-34) Js`

The magnitude of an orbital angular momentum vector of an electron is sqrt(6) (h)/(2pi) into how many components will the vector split if an external field is applied to it ?