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Let E=(-1me^(4))/(8epsilon(0)^(2)n^(2)h^...

Let `E=(-1me^(4))/(8epsilon_(0)^(2)n^(2)h^(2))` be the energy of the `n^(th)` level of H-atom state and radiation of frequency `(E_(2)-E_(1))//h` falls on it ,

A

it will not be absorbed at all

B

some of atoms will move to the first excited state

C

all atoms will be excited to the n=2 state

D

no atoms will make a transition to the n=3 state

Text Solution

Verified by Experts

The correct Answer is:
B, D
Here, `E_(n)=(me^(4))/(8epsilon_(0)^(2)n^(2)h^(2))`
Is the energy of nth level of hydrogen atom. If all the H-atom are in ground state, (n=1), then the radiation of frequency `(E_(2)-E_(1))//h` falling on it may not be absorbed by some of the atoms and move them to the first excited state (n=2). All atoms may not be excited to n=2 state. Further, as `(E_(2)-E_(1))//h` is sufficient only to take the atom form n=1 state to n=2 state, no atoms shall make a transition to n=3 state. Choices (b) and (d) are correct.
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