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In the common emitter amplifier circuit,...

In the common emitter amplifier circuit, Fig. an npn transistor with output voltage of the amplifier as 1 V, the current gain of transistor amplifier is :

A

20

B

25

C

50

D

75

Text Solution

Verified by Experts

The correct Answer is:
C

`A_(v)=V_(0)/V_(i)=betaR_(0)/R_(BE)`
`beta=V_(0)/V_(i)xxR_(BE)/R_(0)=(1V)/(2mV)xx(1kOmega)/(10kOmega)=50`
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