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Prove that the Greatest Integer Function...

Prove that the Greatest Integer Function `f : R->R ,`given by `f (x) = [x]`, is neither one-one nor onto, where [x] denotes the greatest integer less than or equal to x.

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To prove that the Greatest Integer Function \( f: \mathbb{R} \to \mathbb{R} \) defined by \( f(x) = [x] \) (where \([x]\) denotes the greatest integer less than or equal to \( x \)) is neither one-one nor onto, we will analyze both properties step by step. ### Step 1: Proving that \( f \) is not one-one (injective) A function \( f \) is said to be one-one if \( f(a) = f(b) \) implies \( a = b \) for all \( a, b \in \mathbb{R} \). **Example:** Consider the values: ...
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Knowledge Check

  • The greatest integer function f:R rarr R , given by f(x) = [x] is

    A
    one-one
    B
    onto
    C
    both one-one and onto
    D
    neither one-one nor onto
  • lim_(xrarr oo) (log[x])/(x) , where [x] denotes the greatest integer less than or equal to x, is

    A
    0
    B
    1
    C
    -1
    D
    non-existent
  • If f(x)=|x-1|-[x] , where [x] is the greatest integer less than or equal to x, then

    A
    `underset(xto0)lim[f(x)]=0`
    B
    `underset(xto0)lim[f(x)]=1`
    C
    `underset(xto0)lim[(f(x))/(x)]` does not exist
    D
    `underset(xto0)lim[(f(x))/(x)]` exists
  • Similar Questions

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