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If (sin8theta.costheta-sin6theta.cos3the...

If `(sin8theta.costheta-sin6theta.cos3theta)/(cos2theta.costheta-sin3theta.sin4theta)=tan(Ktheta)`, then: `K=...`

A

1

B

2

C

3

D

none of these

Text Solution

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The correct Answer is:
B
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costheta-cos2theta=sin3theta

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

Knowledge Check

  • (sin3theta-cos3theta)/(sintheta+costheta)+1 =

    A
    `2 sin 2theta`
    B
    `2 cos 2theta`
    C
    `tan 2theta`
    D
    `cot 2theta`
  • For any angle theta . (sin2theta+sin4theta+sin6theta+sin8theta)/(cos2theta+cos4theta+cos6theta+cos8theta)=.... (a) tantheta (b) tan 3theta (c) tan5theta (d) none of these

    A
    `tan theta`
    B
    `tan3theta`
    C
    `tan5theta`
    D
    none of these
  • ("sin" 8 theta "cos" theta -"sin" 6 theta "cos"3 theta)/("cos" 2 theta "cos" theta -"sin" 3 theta "sin" 4 theta) is equal to

    A
    `("sin" 7theta-"sin" 3 theta)/("cos" 7theta+"cos" 3 theta)`
    B
    `("sin" 7theta+"sin" 3 theta)/("cos" 7 theta+"cos" 3 theta)`
    C
    `("sin"7theta+"sin"3 theta)/("cos"7theta-"cos" 3 theta)`
    D
    None of these
  • Similar Questions

    Explore conceptually related problems

    (cos6 theta-cos4 theta)/(sin6 theta+sin4 theta)=-tan theta

    (sin theta+cos theta)(1-sin theta cos theta)=sin^3 theta+cos^3 theta

    (sin theta+sin3 theta+sin5 theta)/(cos theta+cos3 theta+cos5 theta)=tan3 theta

    Solve: sin2theta+sin4theta=costheta+cos3theta

    (sin^(3)theta+cos^(3)theta)/(sintheta+costheta)+(sin^(3)theta-cos^(3)theta)/(sintheta-costheta)=