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Planck's constant (h) and de Broglie wav...

Planck's constant (h) and de Broglie wavelength `(lambda)` are related through the equation `h=lambdasqrt(2mE)`, where 'm' and 'E' denote the mass and kinetic energy respectively of the moving particle. The dimensional formula of h is given by

A

`[M^(2)L^(2)T^(-2)]`

B

`[M^(1)L^(2)T^(-1)]`

C

`[M^(1)L^(1)T^(-1)]`

D

`[M^(2)L^(-1)T^(-2)]`

Text Solution

Verified by Experts

The correct Answer is:
b
`h=lambdasqrt(2mE)" but "[E]=[M^(1)L^(2)T^(-2)]and[lambda]=[L^(1)]`
`therefore [h]=[L^(1)][M^(1)M^(1)L^(2)T^(-2)]^(1//2)=[M^(1)L^(2)T^(-1)]`
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