The general electronic configuration of 3d series is ?

Options

A. `[Ar] 3d^(1-10) 4s^(1 or 2)`
B. `[Kr] 3d^(1-10) 4s^(1 or 2)`
C. `[Ar] 3d^(0-10) 4s^(1 or 2)`
D. `[Kr] 3d^(0-10) 4s^(1 or 2)`

Explanation

To determine the general electronic configuration of the 3d series of transition elements, we can follow these steps:

### Step 1: Understand the Transition Elements
The 3d series consists of transition metals with atomic numbers ranging from 21 (Scandium, Sc) to 29 (Copper, Cu). These elements are characterized by the filling of the 3d subshell.

### Step 2: Identify the General Electronic Configuration
The general electronic configuration for transition metals can be described as:
\[ \text{[Noble Gas]} \, (n-1)d^{1-10} \, ns^{1-2} \]
Where:
- \([Noble Gas]\) represents the electron configuration of the nearest noble gas preceding the element.
- \(n\) is the principal quantum number for the outermost shell.

### Step 3: Determine the Noble Gas for the 3d Series
For the 3d series, the nearest noble gas is Argon (Ar), which has the atomic number 18. Therefore, the general electronic configuration for the 3d series can be expressed as:
\[ \text{Ar} \, 3d^{1-10} \, 4s^{1-2} \]

### Step 4: Write the Final Answer
Thus, the general electronic configuration of the 3d series is:
\[ \text{Ar} \, 3d^{1-10} \, 4s^{1-2} \]

### Conclusion
The correct answer is:
**Option A: Argon 3d1 to 10, 4s1 to 2.**

---