Home
Class 12
MATHS
If a particle moving in a straight line ...

If a particle moving in a straight line and its distance x cms from a fixed point O on the line is given by `x=sqrt(1+t^(2))` cms, then acceleration of the particle at t sec. is

A

`(1)/(x^(2))" cm/sec"^(2)`

B

`(-1)/(x^(2))" cm/sec"^(2)`

C

`(1)/(x^(3))" cm/sec"^(2)`

D

`(-1)/(x^(3))" cm/sec"^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • APPLICATION OF DEFINITEINTEGRAL

    NIKITA PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS:(MCQ)|27 Videos

  • BINOMIAL DISTRIBUTION

    NIKITA PUBLICATION|Exercise MCQS|77 Videos

Similar Questions

Explore conceptually related problems

A particle moves in a straight line, so that after t second, the distance x from a fixed point O on the line is given by x=(l-2)^(2)(t-5) . Then

The speed (v) of particle moving along a straight line, when it is of a distance (x) from a fixed point on the line, is given by : v^(2) = 144 - 9x^(2)

Knowledge Check

  • A particle is moving on a straight line and its distance x cms from a fixed point O on the line is given by x=sqrt(t^(2)+1) then the velocity of particle at t=1 is

    A
    `1/(sqrt(2))`
    B
    `1/(sqrt(3))`
    C
    `1/(2sqrt(2))`
    D
    `1/(3sqrt(2))`

  • If the velocity v of a particle moving along a straight line and its distance s from a fixed point on the line are related by v^(2)=a^(2)+s^(2) , then its acceleration equals

    A
    as
    B
    s
    C
    `s^(2)`
    D
    2s

  • A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

    A
    `18m//s^(2)`
    B
    `32m//s^(2)`
    C
    `29m//s^(2)`
    D
    `24m//s^(2)`

    • Similar Questions

    Explore conceptually related problems

    A particle moving in a straight line describes a distance xcm from a fixed point on the line at time ts ,where x=t^(5)-40t^(3)+30t^(2)+180t+240. Find when the acceleration is minimum and find the minimum value of acceleration.

    A particle moves in a straight line such that its distance in 't' secodns from a fixed point is (6t-t^(2)) cm. find its velocity at the end of t=2 se c.

    Speed v of a particle moving along a straight line, when it is a distance X from a fixed point on the line is given by V^(2)=108-9X^(2) (all quantities in S.I. unit). Then

    The speed v of a particle moving along a straight line, when it is at a distance (x) from a fixed point of the line is given by v^2=108-9x^2 (all equation are in CGS units):

    A particle is moving in a straight line. At time t the distance between the particle from its starting point is given by x=t-6t^(2)+t^(3) . Its acceleration will be zero at

    Home
    Profile