Home
Class 12
MATHS
Acoording to Newton's law of cooling, th...

Acoording to Newton's law of cooling, the body cools from `110^(@)C" to "60^(@)C` at room temperature of `10^(@)C` in 1 hour. The body cools to `30^(@)C` after another

A

`(log5)/(log2)-1"hours"`

B

`(log5)/(log2)+1"hours"`

C

`(log5)/(log2)"hours"`

D

`(log2)/(log5)"hours"`

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • APPLICATION OF DEFINITEINTEGRAL

    NIKITA PUBLICATION|Exercise MULTIPLE CHOICE QUESTIONS:(MCQ)|27 Videos

Similar Questions

Explore conceptually related problems

According to ‘Newton’s Law of cooling’, the rate of cooling of a body is proportional to the

A body takes, 4 minutes to cool from 100^(@)C to 70^(@)C , if the room temperature is 25^(@)C , then the time taken to cool from 70^(@)C to 40^(@)C will be

Knowledge Check

  • According to Newton's law of cooling, the body cools from 80^(@)Cand50^(@)C at room temperature of 25^(@)C in 30 minutes. After 1 hours, the temperature of the body is

    A
    `11.36^(@)C`
    B
    `18.18^(@)C`
    C
    `36.36^(@)C`
    D
    `22.72^(@)C`

  • According to Newton's law of cooling, the body cools from 100^(@)Cto60^(@)C in 20 minutes. The temperature of the surrounding being 20^(@)C The body cool down to 30^(@)C in

    A
    40 minutes
    B
    50 minutes
    C
    90 minutes
    D
    60 minutes

  • According to Newton's law of cooling ,the rate of cooling of a body is proportional to the

    A
    temperature of the body
    B
    temperature of the surrounding
    C
    difference of the temperature of the body and its surroungs
    D
    none of these

    • Similar Questions

    Explore conceptually related problems

    A body cools from 50^(@)C to 40^(@)C in 5 min. The surroundings temperature is 20^(@)C . In what further times (in minutes) will it cool to 30^(@)C ?

    A body cools from 50^(@)C to 49.9^(@)C in 5 s. the temperature of the surroundings is 30^(@)C . How long will the body, take to cool from 40^(@)C to 39.9^(@)C ?

    A body cools from 80^(@)C to 60^(@)C in 5 minutes. Then its average rate of cooling is

    A body cools from 70^(@)C to 60^(@)C in 8minute The same body cools from 60^(@)C to 50^(@)C in .

    A cup of tea cools from 80^(@)C" to "60^(@)C in one minutes. The ambient temperature is 30^(@)C . In cooling from 60^(@)" to "50^(@)C it will take-

    Home
    Profile