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The acceleration due to gravity on a pla...

The acceleration due to gravity on a planet of mass `10^(25)` Kg and radius 2580 Km in `ms^(-2)` is

A

1

B

10

C

20

D

100

Text Solution

Verified by Experts

The correct Answer is:
d

`g=(GM)/(R^(2))=(6.67xx10^(-11)xx10^(25))/((2580xx10^(3))^(2))`
`=(6.67xx10^(14))/(6.66xx10^(12))=10^(+2)=100ms^(-1)`
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Knowledge Check

  • If the acceleration due to gravity on a planet is 6.67 ms^(-2) and its radius is 4 xx 10^(6) m, then the mass of the planet is _____ .

    A
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    D
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  • Acceleration due to gravity at earth's surface is 10 m ^(-2) The value of acceleration due to gravity at the surface of a planet of mass 1/2 th and radius 1/2 of f the earth is -

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    `5 ms ^(-2)`
    B
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    C
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    D
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  • Acceleration due to gravity at earth's surface is 10ms^(-2) . The value of acceleration due to gravity at the surface of a planet of mass (1/5)^(th) and radius 1/2 of the earth is

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    D
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