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The acceleration due to gravity on a pla...

The acceleration due to gravity on a planet of mass `10^(25)` Kg and radius 2580 Km in `ms^(-2)` is

A

1

B

10

C

20

D

100

Text Solution

Verified by Experts

The correct Answer is:
d
`g=(GM)/(R^(2))=(6.67xx10^(-11)xx10^(25))/((2580xx10^(3))^(2))`
`=(6.67xx10^(14))/(6.66xx10^(12))=10^(+2)=100ms^(-1)`
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