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The product of positive charge and dista...

The product of positive charge and distance between the two charges is

A

electric dipole

B

electric dipole moment

C

electric flux

D

electric intensity

Text Solution

Verified by Experts

The correct Answer is:
B
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The force of repulsion between two point charges is F, when these are at a distance of 1 m . Now the point charges are replaced by spheres of radii 25 cm having the charge same as that of point charges. The distance between their centres is 1 m , then compare the force of repulsion in two cases.

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Knowledge Check

  • The product of the magnitude of the charge and the distance between the centres of positive and negative charge is called

    A
    charge ratio
    B
    dipole moment
    C
    current flow
    D
    magnetic moment

  • The force of repulsion between two point charges is F, when these are at distance 0.5m apart. Now the point charges are replaced by spheres of radii 5 cm each having the same charge as that of the respective point charge. The distance between their centres is again kept 0.5 m. Then the force of repulsion will

    A
    increase
    B
    decrease
    C
    remain F
    D
    become `(10 F)/9`

  • A positive charge +q_1 is located to the left of a negative charge -q_2 . On a line passing through the two charges, there are two places where the total potential is zero. The first place is between the charges and is 4.00 cm to the left of the negative charge. The second place is 7.00 cm to the right of the negative charge. What is the distance between the charges?

    A
    `0.637 m`
    B
    `0.773 m`
    C
    `0.442`
    D
    `0.187 m`

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