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A solution of CaCl(2) is mol/litre, then...

A solution of `CaCl_(2)` is mol/litre, then the moles of chloride ions in 500 mL will be

A

0.25

B

0.5

C

0.75

D

1

Text Solution

Verified by Experts

The correct Answer is:
B
`M=n/(V(mL)) xx 1000`
`0.5=n/500 xx 1000`
`n=0.5/2=0.25` moles of `CaCI_(2)`
`As CaCI_(2) hArr Ca^(2+) + 2 CI^(-)`
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