An aqueous solution of a non-electrolyte solute boils at `100.52^(@)C`. The freezing point of the solutiion will be (`K_(f) = 1.86 K kg "mol"^(-1), K_(b) = 0.52 K kg "mol"^(-1)`)

Options

A. `0^(@)C`
B. `-1.86^(@)C`
C. `1.86^(@)C`
D. none of the above.

Answer

B

Explanation

`Delta T_(b) = K_(b) xx m`
`i=e.,0.52 = 0.52 xx m` or m=1
`Delta T_(f) =K_(f) xx m = 1.86 xx 1 = 1.86^(@)`
`i.e., T_(f) = T_(F)^(@)-Delta T_(f) = 0^(@) C-1.86^(@)C=1.86^(@)C`