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Find four consecutive terms in an A.P. s...

Find four consecutive terms in an A.P. such that the sum of the middle two terms is 18 and product of the two end terms is 45.

Text Solution

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The correct Answer is:
3,7,11,15 or 15,11,7,3
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Knowledge Check

  • If the product of the first four consecutive terms of a G.P is 256 and if the common ratio is 4 and the first term is positive, then its 3rd term i s ...........

    A
    8
    B
    `1/16`
    C
    `1/32`
    D
    16

  • If the nth term of an A.P. is t_(n) =3 -5n , then the sum of the first n terms is ………

    A
    `n/2 [1-5n]`
    B
    `n(1-5n)`
    C
    `n/2 (1+5n)`
    D
    `n/2(1+n)`

  • In an A.P., the first term is 2 and the sum of first five terms is 5. Then the 31th term is

    A
    13
    B
    17
    C
    `-13`
    D
    `27/2`

    • Similar Questions

    Explore conceptually related problems

    A geometric series consists of four terms and has a positive common ratio. The sum of the first two terms is 9 and sum of the last two terms is 36. Find the series.

    Find three consecutive terms in terms in an A.P. whose sum is -3 and the product of their cubes id 512.

    Find a G.P. for which sum of the first two terms is – 4 and the fifth term is 4 times the third term.

    In a G.P. the product of three consecutive terms is 27 and the sum of the product of two terms taken at a time is (57)/(2) . Find the three terms.

    If the sum of m terms of an A.P. is same as the sum of its n terms, then the sum of its (m+n) terms is

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