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Find the equation of the circle which cu...

Find the equation of the circle which cuts orthogonally the circle `x^(2)+y^(2)-4x+2y-7=0` and having the centre at (2, 3).

Answer

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Find the equation of the circle which cuts orthogonally the circle x^2 + y^2 - 4x + 2y - 7 = 0 and having a center at (2,3).

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Knowledge Check

  • The equation of the circle which cuts orthogonally the circle x^(2) + y^(2) - 4x + 2y-7 = 0 and having centre at (2, 3) is,

    A
    `3x^(2)- 3y^(2) + 2x- 12y + 2 = 0`
    B
    `x^(2)+ y^(2) + 6x + 4y + 19 = 0`
    C
    `x^(2)+y^(2)-2x + 4y + 2 = 0`
    D
    `x^(2) + y^(2) - 4x - 6y + 9 = 0`
  • The equation of the circle which cuts orthogonally the circle x^(2) + y^(2) - 4x + 2y-7 = 0 and having centre at (2, 3) is,

    A
    `3x^(2)- 3y^(2) + 2x- 12y + 2 = 0`
    B
    `x^(2)+ y^(2) + 6x + 4y + 19 = 0`
    C
    `x^(2)+y^(2)-2x + 4y + 2 = 0`
    D
    `x^(2) + y^(2) - 4x - 6y + 9 = 0`
  • If the equation of the circle which cuts orthogonally the circle x^(2) +y^(2) - 4x + 2y - 7 = 0 and having centre at (2,3) is x^(2) + y^(2) = 2ax + 2by + c = 0 then the assending order of a, b, c is

    A
    a,b,c
    B
    b,c,a
    C
    b,a,c
    D
    a,c,b
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