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The energy required to break one mole of...

The energy required to break one mole of `Cl-Cl` bonds in `Cl_2` is `242 kJ mol^-1`. The longest wavelength of light capable of breaking a since `Cl-Cl` bond is

A

594 nm

B

640 nm

C

700 nm

D

494 nm

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The correct Answer is:
To find the longest wavelength of light capable of breaking a single Cl-Cl bond in Cl2, we can follow these steps: ### Step 1: Convert the energy from kJ/mol to J/molecule The energy required to break one mole of Cl-Cl bonds is given as 242 kJ/mol. We need to convert this energy into joules per molecule because the energy of a single bond is what we are interested in. 1 kJ = 1000 J, so: \[ 242 \text{ kJ/mol} = 242 \times 1000 \text{ J/mol} = 242000 \text{ J/mol} \] Now, to find the energy per molecule, we divide by Avogadro's number (approximately \(6.022 \times 10^{23}\) molecules/mol): \[ E_{\text{per molecule}} = \frac{242000 \text{ J/mol}}{6.022 \times 10^{23} \text{ molecules/mol}} \approx 4.02 \times 10^{-19} \text{ J/molecule} \] ### Step 2: Use the energy-wavelength relationship The energy of a photon is related to its wavelength by the equation: \[ E = \frac{hc}{\lambda} \] where: - \(E\) is the energy of the photon (in joules), - \(h\) is Planck's constant (\(6.626 \times 10^{-34} \text{ J s}\)), - \(c\) is the speed of light (\(3.00 \times 10^8 \text{ m/s}\)), - \(\lambda\) is the wavelength (in meters). Rearranging the equation to solve for wavelength gives: \[ \lambda = \frac{hc}{E} \] ### Step 3: Substitute the values into the equation Now we can substitute the values we have into the equation: \[ \lambda = \frac{(6.626 \times 10^{-34} \text{ J s})(3.00 \times 10^8 \text{ m/s})}{4.02 \times 10^{-19} \text{ J}} \] Calculating this gives: \[ \lambda \approx \frac{1.9878 \times 10^{-25} \text{ J m}}{4.02 \times 10^{-19} \text{ J}} \approx 4.94 \times 10^{-7} \text{ m} \] ### Step 4: Convert meters to nanometers To express the wavelength in nanometers (1 nm = \(10^{-9}\) m): \[ \lambda \approx 4.94 \times 10^{-7} \text{ m} = 494 \text{ nm} \] ### Final Answer The longest wavelength of light capable of breaking a single Cl-Cl bond is approximately **494 nm**. ---

To find the longest wavelength of light capable of breaking a single Cl-Cl bond in Cl2, we can follow these steps: ### Step 1: Convert the energy from kJ/mol to J/molecule The energy required to break one mole of Cl-Cl bonds is given as 242 kJ/mol. We need to convert this energy into joules per molecule because the energy of a single bond is what we are interested in. 1 kJ = 1000 J, so: \[ 242 \text{ kJ/mol} = 242 \times 1000 \text{ J/mol} = 242000 \text{ J/mol} ...
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Knowledge Check

  • The energy required to break one mole of Cl-Cl bonds in Cl_(2) is 242 kJ mol^(-1) . The longest wavelength of light capable of breaking a single Cl-Cl bond is (C=3xx10^(8)ms^(-1)andN=6.02xx10^(23)mol^(-1))

    A
    594 nm
    B
    640 nm
    C
    700 nm
    D
    494 nm
  • The energy required to break one mole of Cl- Cl bonds in Cl_(2) " is " 242 " kJ mol"^(-1) . The longest wavelength of light capable of breaking a single Cl-Cl bond is (c=3xx10^(8) ms^(-1) and N_(A)=6.02xx10^(23) " mol"^(-1))

    A
    594 mm
    B
    640 mm
    C
    700 mm
    D
    494 mm
  • The energy required to break one mole of CL-CL bonds cl^2 is 242 kJ mol^-1. The largest wavelength of light capable of breaking a single CL-CL bond is

    A
    700 nm
    B
    494 nm
    C
    596 nm
    D
    640 nm
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