The uncertainty in position and velocity of the particle are `0.1 nm` and `5.27 xx 10^-27 ms^-1` respectively. Then the mass of the particle is : `(h = 6.625 xx 10^-34 J s)`.

Options

A. 200 g
B. 300 g
C. 100 g
D. 1000 g

Answer

C

Explanation

( c) `Delta x = 0.1 xx 10^-9 m`
`Delta V = 5.27 xx 10^-27 ms^-1`
`:. Delta x xx m Delta V = (h)/(4 pi)`
:. `0.1 xx 10^-9 xx m xx 5.27 xx 10^-27 = 0.527 xx 10^-34`
`:. m = 0.1 kg = 100 g`.