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4.8 g of C (diamond) on complete combust...

`4.8 g` of `C` (diamond) on complete combustion evolves`1584 kJ` of heat. The standard heat of formation of gaseous carbon is `725 kJ//mol`. The energy required for the process
C(graphite) `rarr` C(gas)
C(diamond) `rarr` C(gas) are

A

`725,727`

B

`727,725`

C

`725,723`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
The expression for standard heat of formation of gaseous carbon is
`C("graphite")rarrC("gas")`
`DeltaH=725KJ//mol`
As graphite is thermodynamically more stable than diamond so the heat required to convert graphic to gaseous mond so the heat required to convert graphic to gaseous carbon should be more:
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