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On a given condition, the equilibrium co...

On a given condition, the equilibrium concentration of H, `H_(2)` and `I_(2)` are `0.80` , `0.10` and `0.10` mole/litre. The equilibrium constant for the reaction `H_(2) + I_(2) hArr 2HI` will be

A

64

B

12

C

8

D

`0.8`

Text Solution

Verified by Experts

The correct Answer is:
A
`H_(2) + I_(2)hArr 2HI, [HI] = 0.80, [H_(2)] = 0.10, [I_(2)] = 0.10`
`K_(c) = ([HI]^(2))/([H_(2)][I_(2)]) = (0.80xx0.80)/(0.10xx0.10) = 64`
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Knowledge Check

  • On a give condition, the equilibrium concentration of HI, H_(2) and I_(2) are 0.80,1.10 mole/litre. The equlibrium constant for the reaction H_(2)+I_(2)hArr 2HI will be

    A
    64
    B
    12
    C
    8
    D
    `0.8`

  • The unit of equilibrium constant for the reaction H_(2)+I_(2)hArr2HI is

    A
    `mol^(-1)L`
    B
    `mol^(-2)L`
    C
    mol `L^(-1)`
    D
    None of these

  • Unit of equilibrium constant for the reversible reaction H_(2) + I_(2)hArr 2HI is

    A
    `mol^(-1)` litre
    B
    `mol^(-2)` litre
    C
    mol `litre^(-1)`
    D
    None of these

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