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In a balanced wheat stone bridge, curren...

In a balanced wheat stone bridge, current in the galvanometer is zero. If remains zero when-
`(1)` battery emf is increased
`(2)` all resistance are increased by `10`ohms
`(3)` all resistance are made five times
`(4)` the battery and the galvanometer are intercharged

A

only (1) is correct

B

(1),(2) and (3) are correct

C

(1),(3) and (4) are correct

D

(1) and (3) are correct

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the conditions under which a Wheatstone bridge remains balanced. A Wheatstone bridge is balanced when the ratio of the resistances in one branch is equal to the ratio of the resistances in the other branch, which can be expressed as: \[ \frac{P}{Q} = \frac{R}{S} \] Where \(P\), \(Q\), \(R\), and \(S\) are the resistances in the bridge. ### Step-by-Step Solution: 1. **Condition of Balance**: In a balanced Wheatstone bridge, the current through the galvanometer is zero. This condition is maintained as long as the ratio of the resistances remains unchanged. 2. **Increasing the Battery EMF**: - If we increase the EMF of the battery, it does not affect the ratio of the resistances \(P\), \(Q\), \(R\), and \(S\). - Therefore, the balance condition \(\frac{P}{Q} = \frac{R}{S}\) still holds true. - **Conclusion**: The current in the galvanometer remains zero. 3. **Increasing All Resistances by 10 Ohms**: - If we increase each resistance by 10 ohms, the new resistances become \(P + 10\), \(Q + 10\), \(R + 10\), and \(S + 10\). - The new balance condition becomes \(\frac{P + 10}{Q + 10} \neq \frac{R + 10}{S + 10}\) (this will not hold true for arbitrary values of \(P\), \(Q\), \(R\), and \(S\)). - **Conclusion**: The current in the galvanometer will not remain zero. 4. **Making All Resistances Five Times**: - If all resistances are multiplied by 5, we have new resistances as \(5P\), \(5Q\), \(5R\), and \(5S\). - The balance condition becomes \(\frac{5P}{5Q} = \frac{5R}{5S}\), which simplifies to \(\frac{P}{Q} = \frac{R}{S}\). - **Conclusion**: The current in the galvanometer remains zero. 5. **Interchanging the Battery and Galvanometer**: - Interchanging the battery and the galvanometer does not affect the balance condition of the Wheatstone bridge. - The ratios of the resistances remain unchanged. - **Conclusion**: The current in the galvanometer remains zero. ### Final Results: - The current in the galvanometer remains zero in the following cases: - (1) When the battery EMF is increased. - (3) When all resistances are made five times. - (4) When the battery and the galvanometer are interchanged. Thus, the correct options are **1, 3, and 4**.
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Figure shows a balanced Wheatstone's bridge (1) If P is slightly increased, the current in the galvanometer flow from A to C. (2) If P is slightly increased, the current in the galvanometer flows C to A. (3) If Q is slightly increased, the current in the galvanometer flows from C to A. (4) If Q is slightly increased, the current in the galvanometer flows from A to C.

If the current current sensitivity of a moving coil galvanometer is increased by 20% , its resistance also increases by 1*5 times. How will the voltage sensitivity of the galvanometer be affected?

Knowledge Check

  • The initial rate of increase of current, when a battery of emf 6 V is connected in series with an inductance of 2 H and resistance 12Omega , is

    A
    `0.5As^(-1)`
    B
    `1As^(-1)`
    C
    `3As^(-1)`
    D
    `3.5As^(-1)`
  • If all resistors in the shown network are of equal resistance, and the battery is of emf equal to 10 V and internal resistance equal to 1 Omega , what should be resistance of each resistor so that the battery delivers maximum power

    A
    `1Omega`
    B
    `2Omegga`
    C
    `3Omega`
    D
    `4Omega`
  • When a resistance of 2 ohm is placed across a battery the current is 1 A and when the resistance across the terminals is 17 ohm, the current is 0.25A. The emf of the battery is

    A
    4.5 V
    B
    5V
    C
    3V
    D
    6V
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