Home
Class 11
PHYSICS
A uniform rod of length l and mass M rot...

A uniform rod of length `l` and mass `M` rotating about a fixed vertical axis on a smooth horizontal table. It elastically strikes a particle placed at a distance `l//3` from its axis and stops. Mass of the particle is -
.

A

`3 M`

B

`(3M)/(4)`

C

`(3 M)/(2)`

D

`(4M)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
B

From conservation of angular momentum
`I omega = mv (l)/(3) rArr (Ml^(2))/(12) xx omega = mv (l)/(m)`
`v = (Ml omega)/(4 m)` ….(1)
From conservation of `K.E`
`(1)/(2) I omega^(2) = (1)/(2) mv^(2)` ….(2)
from (1) & (2)
`(1)/(2) (Ml^(2))/(12) xx omega^(2) = (1)/(2) m xx ((Ml omega)/(4m))^(2) rArr m = (3)/(4) M`.
.
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

A uniform rod of mass M and length a lies on a smooth horizontal plane. A particle of mass m moving at a speed v perpendicular to the length of the rod strikes it at a distance a/4 from the centre and stops after the collision. Find a. the velocity of the cente of the rod and b. the angular velocity of the rod abut its centre just after the collision.

A uniform rod of mass M and length L lies on a smooth horizontal plane. A particle of mass m moving at a speed v perpendicular to the length of the rod strikes it at a distance L//6 from the center and stops after the collision. Find (a) the velocity of center of mass of rod and (b) the angular velocity of the rod about its center just after collision.

Knowledge Check

  • A rod AB of mass m and length l is rotating about a vertical axis as shown. It's moment of inertia about this axis is :

    A
    `(ml^(2))/3`
    B
    `(ml^(2))/4`
    C
    `(ml^(2))/16`
    D
    `(ml^(2))/12`
  • A uniform rod of mass m , length l rests on a smooth horizontal surface. Rod is given a sharp horizontal impulse p perpendicular to the rod at a distance l//4 from the centre. The angular velocity of the rod will be

    A
    `(3p)/(ml)`
    B
    `p/(ml)`
    C
    `p/(2ml)`
    D
    `(2p)/(ml)`
  • A uniform rod of length l and mass 2m rests on a smooth horizontal table. A point of mass m moving horizontally at right angle to the rod with velocity v collides with one end of the rod and sticks to it, then:

    A
    angular velocity of the system after collision is `v/l`
    B
    angular velocity of the system after collision is `v/(2l)`
    C
    the loss in kinetic enerlgy of the system as a whole as a result of the collision is `(mv^(2))/6`
    D
    the loss in kinetic energy of the system as a whole as a result of the collision is `(7mv^(2))/24`
  • Similar Questions

    Explore conceptually related problems

    A uniform rod of length l and mass 2 m rests on a smooth horizontal table. A point mass m moving horizontally at right angles to the rod with velocity v collides with one end of the rod and sticks it. Then

    A uniform rod AB of mass 3m and length 2l is lying at rest on a smooth horizontal table with a smooth vertical axis through the end A. A particle of mass 2m moves with speed 2u across the table and strikes the rod at its mid-point C if the impact is perfectly elastic. Find the speed of the particle after impact if (a). It strikes rod normally, (b). Its path before impact was inclinded at 60^(@) to AC.

    A uniform rod of mass m and length l rotates in a horizontal plane with an angular velocity omega about a vertical axis passing through one end. The tension in the rod at a distance x from the axis is

    A conical pendulum, a thin uniform rod of length l and mass m , rotates uniformly about a vertical axis with angular velocity omega (the upper end of the rod is hinged). Find the angle theta between the rod and the vertical.

    A uniform rod AB of length L and mass m is suspended freely at A and hangs vertically at rest when a particle of same mass m is fired horizontally with speed v to strike the rod at its mid point. If the particle is brought to rest after the impact. Then the impulsive reaction at A is horizontal direction is