Home
Class 11
PHYSICS
Torque (vec tau) acting on a rigid body ...

Torque `(vec tau)` acting on a rigid body is defined as `vec tau = vec A xx vec L`, where `vec A` is a constant vector and `vec L` is angular momentum of the body. The magnitude of the angular momentum of the body remains same.
`vec tau` is perpendicular to `vec L` and hence torque does not deliver any power to the body.

A

Statement-1 is True, Statement-2 is Ture , Statement -2 is a correct explanation for statement -1.

B

Statement-1 is True, Statement-2 is True , Statement-2 is NOT a correct explanation fro Statement -1.

C

Statement-1 is True, Statement-2 is False.

D

Statement-1 is False, Statement-2 is True.

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

The torque tau on a body about a given point is found to be equal to A x L, where A is constant vector and L is the angular momentum of the body that point. From this, it follows that

Angular momentum of a rigid body rotating about a fixed Axis with angular velocity vec omega

Knowledge Check

  • The torque vec tau on a body about a given point is found to be equal to vec A xx vec L where vec A is a constant vector and vec L is the angular momentum of the body about the point. From this its follows that -

    A
    `(d vec(L))/(dt)` is perpendicular to `vec L` at all instants of time.
    B
    the components of `vec L` in the direction of `vec A` does not change with time.
    C
    the magnitude of `vec L` does not change with time
    D
    `vec L` does not change with time.
  • If the angular momentum of an electron is vec(J) then the magnitude of the magnetic moment will be

    A
    `(eJ)/m`
    B
    `(eJ)/(2m)`
    C
    `eJ 2m`
    D
    `(2m)/(eJ)`
  • A body is acted upon by a constant torque . In 4 seconds its angular momentum changes from L to 4L . The magnitude of the torque is

    A
    `(L)/(4)`
    B
    `(3L)/(4)`
    C
    3L
    D
    12L
  • Similar Questions

    Explore conceptually related problems

    If vec(tau)xxvec(L)=0 for a rigid body, where vec(tau)= resultant torque & vec(L) =angular momentum about a point and both are non-zero. Then

    The relation between the torque tau and angular momentum L of a body of moment of inertia I rotating with angular velocity omega is

    The torque tau acting on an electric dipole of dipole momtn vec(p) in an electric field vec( E ) is

    The linear velocity of a particle on a rotating body is given by vec v = vec omega xx vec r" where "vec omega is the angular velocity and vec r is the radius vector. What is the value of |v| if vec omega = hati -2hatj+2hatk and vec r =4hatj-3hatk ?

    Two vectors vec(A)andvec(B) are acting in the same plane and the vector vec( C ) is perpendicular to the plane. The resultant of these vectors.