A block of mass 0.9 kg attached to a spr...

A block of mass `0.9 kg` attached to a spring of force constant `k` is lying on a frictionless floor. The spring is compressed to `sqrt(2) cm` and the block is at a distance `1//sqrt(2) cm` from the wall as shown in the figure. When the block is released, it makes elastic collision with the wall and its period of motion is `0.2 sec`. Find the approximate value of `k`

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Verified by Experts

The correct Answer is:

`100 Nm^(-1)`

Figure

In the figure, the block of mass m, attached to the spring of stiffness k is in correct with the completely elastic wall, and the compression in the spring is e. The spring is compressed further by e by displacing the block towards left and is then released. If the collision between the block and the wall is completely eleastic then the time period of oscillation of the block will be

`(2pi)/3)sqrt(m/k)`

`(2pi)sqrt(m/k)`

`pi/3sqrt(m/k)`

`pi/6sqrt(m/k)`

A block of mass m compresses a spring iof stifffness k through a distacne l//2 as shown in the figure .If the block is not fixed to the spring the period of motion of the block is

`2pisqrt(m/k)`

`(pi+4)sqrt(m/k)`

`(1+pi)sqrt(m/k)`

None of these

One end of aspring of force constant k is fixed to a verticle wall and the other to a block of mass m resing on a smooth horizontal surface There is another and wall at a distance x_(0) from the block The spring is then compressed by 2x_(0) and released The time taken to at the wall is

`(1)/(6)pi sqrt((k)/(m))`

`sqrt((k)/(m))`

`(2pi)/(3) sqrt((m)/(k))`

`(pi)/(4) sqrt((k)/(m))`

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