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In which delocalisation of positive char...

In which delocalisation of positive charge is possible?

A

B

C

D

Text Solution

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The correct Answer is:
To determine in which scenario the delocalization of positive charge is possible, we will analyze each option step by step. ### Step 1: Analyze Option A - **Structure**: A nitrogen (N) atom with three hydrogen (H) atoms and a positive charge. - **Delocalization Attempt**: If we try to delocalize the positive charge by turning a bond, we would end up with a structure where nitrogen has 10 electrons. - **Conclusion**: This is not possible because nitrogen can only accommodate a maximum of 8 electrons in its valence shell. Therefore, positive charge delocalization is not possible in option A. ### Step 2: Analyze Option B - **Structure**: A nitrogen atom with two hydrogen atoms and a double bond, along with a positive charge. - **Delocalization Attempt**: Trying to delocalize the positive charge by shifting a bond results in nitrogen again having 10 electrons. - **Conclusion**: This is also not possible, as nitrogen cannot exceed its octet. Thus, positive charge delocalization is not possible in option B. ### Step 3: Analyze Option C - **Structure**: A positively charged hydroxyl group (OH2+). - **Delocalization Attempt**: Attempting to delocalize the positive charge by breaking a bond leads to a situation where the oxygen would have more than 8 electrons. - **Conclusion**: This is not feasible since oxygen cannot accommodate more than 8 electrons. Hence, positive charge delocalization is not possible in option C. ### Step 4: Analyze Option D - **Structure**: A structure with multiple double bonds and a positive charge. - **Delocalization Attempt**: If we attempt to delocalize the positive charge by breaking a bond, we can create a double bond while maintaining the octet rule for the involved atoms. - **Conclusion**: In this case, the delocalization of positive charge is possible without violating the octet rule. Therefore, option D is the correct answer. ### Final Answer The delocalization of positive charge is possible in **Option D**. ---

To determine in which scenario the delocalization of positive charge is possible, we will analyze each option step by step. ### Step 1: Analyze Option A - **Structure**: A nitrogen (N) atom with three hydrogen (H) atoms and a positive charge. - **Delocalization Attempt**: If we try to delocalize the positive charge by turning a bond, we would end up with a structure where nitrogen has 10 electrons. - **Conclusion**: This is not possible because nitrogen can only accommodate a maximum of 8 electrons in its valence shell. Therefore, positive charge delocalization is not possible in option A. ### Step 2: Analyze Option B ...
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Knowledge Check

  • In which of the following carbocations, delocalisation of positive charge is possible :

    A
    B
    C
    D
    `overset(o+)(C )H_(2)-O-CH_(3)`
  • In which cases delocalisation of charge is possible ?

    A
    B
    `overset(Theta)O-P(CH_(3))_(2)`
    C
    `overset(Theta)O-overset(o+)P(CH_(3))_(2)`
    D
    `overset(Theta)O-B(CH_(3))_(2)`
  • Assertion: Pyrrolidince (II) is more basic than pyrrole (I) Reason: Protonated pyrrole has delocalisation of positive charge in aromatic ring.

    A
    If both assertion and reason are true and the reason is the correct explanation of the assertion.
    B
    If both assertion and reason are true and the reason is the correct explanations of the assertion
    C
    If assertion is true but reason is false.
    D
    If assertion is false but reason is true.
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