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An ideal gas with the adiabatic exponent...

An ideal gas with the adiabatic exponent `gamma` goes through a direct (clockwise) cycle conisting of adiabatic, isobaric, and isochoric lines. Find the efficiency of the cycle if in the adiabatic process the volume of the ideal gas.
(a) increases n-fold ,
(b) decreases n-fold.

Text Solution

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To find the efficiency of a cycle consisting of adiabatic, isobaric, and isochoric processes for an ideal gas, we need to analyze both scenarios: when the volume increases n-fold during the adiabatic process and when it decreases n-fold. ### Step-by-Step Solution: **Step 1: Understand the Cycle** - The cycle consists of three processes: 1. **Adiabatic Process (1 to 2)**: No heat exchange (Q = 0). 2. **Isobaric Process (2 to 3)**: Constant pressure. ...
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Knowledge Check

  • Helium gas goes through a cycle ABCDA (consisting of two isochoric and isobaric lines) as shown in figure Efficiency of this cycle is nearly: (Assume the gas to be close to ideal gas)

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    `15.4%`
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    `15.4%`
    B
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    `10.5%`
    D
    `12.5%`

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