Home
Class 12
PHYSICS
A small current-carrying coil having a ...

A small current-carrying coil having a megantic moment `p_(m)` is located at the axis of a round loop of radius `R` with current `I` flowing thorough it. Find the magnitude of the vector force applied to the coil if its distance from the centre of the loop is equal to `x` and the vector `p_(m)` coincides in direction with the axis of the loop.

Text Solution

Verified by Experts

`F_(x) = p_(m) (del)/(del x) B_(x)`
But, `B_(x) = (mu_(0) I)/(4pi) int (Rdl)/((x^(2) + R^(2))^(3//2)) (3)/(2) = (mu_(0) IR^(2))/(2(x^(2) + R^(2))^(3//2))`
So `F = (mu_(0))/(4pi) (I.2pi R^(2))/((x^(2) + R^(2))^(5//2)) (3)/(2) . 2x p_(m)`
`= (mu_(0) 6pi R^(2) I p_(m) x)/(4pi (x^(2) + R^(2))^(5//2))`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTRODYNAMICS

    IE IRODOV, LA SENA & SS KROTOV|Exercise Electromagnetic Induction|84 Videos

  • ELECTRODYNAMICS

    IE IRODOV, LA SENA & SS KROTOV|Exercise Motion Of Charged Particle In Magnetic Field|36 Videos

  • ELECTRODYNAMICS

    IE IRODOV, LA SENA & SS KROTOV|Exercise Electric Current|72 Videos

  • ELECTRICITY AND MAGNETISM

    IE IRODOV, LA SENA & SS KROTOV|Exercise All Questions|6 Videos

  • ELECTROMAGNETISM

    IE IRODOV, LA SENA & SS KROTOV|Exercise All Questions|24 Videos

Similar Questions

Explore conceptually related problems

A square loop of wire, edge length a, carries a current i. Compute the magnitude of the magnetic field produced at a point on the axis of the loop at a distance x from the centre.

A small current-carrying loop is located at a distance r from a long straight conductor with current I . The magnetic moment of the loop is equal to p_(m) . Find the magnitude and direction of the force vector applied to the loop if the vector p_(m) (a) is parallel to the stratight conductor, (b) is oriented along the radius vector r , (c) coincides in direction with the magnetic field produced by the current I the point where the loop is located.

Knowledge Check

  • The radius of a circular loop is r and a current I is flowing is it. The equivalent magnetic moment will be

    A
    Ir
    B
    `2 pi Ir`
    C
    `I pi r^(2)`
    D
    `(1)/(r^(2))`

  • Magnetic field intensity H at the centre of a circular loop of radius r carrying current I e.m.u. is

    A
    `(r )/(I)` oersted
    B
    `(2pi)/(r )` oersted
    C
    `(I)/(2pi r)` oersted
    D
    `(2pi r)/(I)` oersted

  • A circular coil of radius R carries an electric current. The magnetic field due to the coil at a point on the axis of the coil located at a distance r from the centre of the coil, such that r > > R , varies as

    A
    `1/r`
    B
    `1/(r^(3//2))`
    C
    `1/(r^2)`
    D
    `1/(r^3)`

    • Similar Questions

    Explore conceptually related problems

    The radius of a circular loop is r and a current i is flowing in it. The equivalent magnetic moment will be

    A circular loop of radius R carries a current I. Obtain an expression for the magnetic field at a point on its axis at a distance x from its centre.

    A circular coil of radius R carries an electric current. The magnetic field due to the coil at a point on the axis of the coil located at a distance r from the centre of the coil, such that r gtgt R , varies as

    Radius of current carrying coil is 'R'. Then ratio of magnetic fields at the centre of the coil to the axial point, which is Rsqrt(3) distance away from the centre of the coil :-

    Find the magnetic moment of a thin round loop with current if the radius of the loop is equal to r and the magnetic induction at its centre is equal to X.

    Home
    Profile