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A long straight wire carrying a current...

A long straight wire carrying a current `I` and a `II`- shaped conductor with siding connector are located in the same plane as shown in Fig. The connector of length `l` and resistance `R` sides to the right with a current induced in the loop as a function of separation `r` between the connector and the stragiht wire. The resistance of the `II`-shaped conductor and the self-induced of the loop are assumed to be negligible.

Text Solution

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Field, due to the current carrying wire in the region, right to it, is directed into the plane of the paper and its magnitude is given by,
`B = (mu_(0))/(2pi) (i)/(r)` where `r` is the perpendicular distance from the wire.
As `B` is same length of the rod thus motinal e.m.f
`xi_(i n) = |-int_(1)^(2) (vec(v) xx vec(B)) . d vec(l)| = vB l`
and it is directed in the sense of `(vec(v) xx vec(B))`
So, current (induced) in teh loop,
`i_(i n) = (xi_(i n))/(R) = (1)/(2) (mu_(0) I vi)/(pi R r)`
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Knowledge Check

  • A straight conductor carrying current I and a loop closed by a sliding connector of resistance R lie in the same plane . The connector slides towards right with a uniform velocity v . The induced current generated in the loop in terms of distance r of the connector from the straight conductor will be __

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    D
    None of these
  • A long straight wire is carrying a current of 25 A. A squre loop of side length 10 cm carrying a current of 15 A, is placed 2 cm from the wire as shown in figure. The force on the loop is

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    `3.1xx10^(-3)N` towards the wire
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    B
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