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Given standard electrode potentials F...

Given standard electrode potentials
` Fe^(2+) + 2e^(-) rarr Fe, E^@ =- 0. 44 V ` ………………(1)
` Fe^(3+) + 3e^(-) rarr Fe, E^@ =- 0. 036 V` ………….(2)
The standard electrode potential `E^@ ` for
`Fe^(3+) + e^(-) rarr Fe^(2+)` is.

A

` -0. 476 V`

B

` -0. 404 V`

C

`0. 404 V`

D

` +0. 772 V`

Text Solution

Verified by Experts

The correct Answer is:
D
`Fe^(2+) + 2e rarr Fe, DeltaG_1^@ =- nE^2 F=- 2 F (-0.44)`
`= 0.88 F`
`Fe^(2+) + 2e rarr Fe, DeltaG_2^@ =- nE^2 F=- 2 F (-0.036)`
` =0.108 F`
On subtracting (1) from (2)
`Fe^(3+) +d^- rarr Fe^(2+)` or `Delta G =- 0. 772 F`
or ` Delta G =- nE^@ F=- 0.772F`
Or ` E^@ = (0.772 )/1 -.0772 V`.
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