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If 3A rarr 2B, then the rate of reaction...

If `3A rarr 2B`, then the rate of reaction of `+ (dB)/(d t)` is equal to

A

`+2 (d[A])/(d t)`

B

`-(1)/(3) (d[A])/(d t)`

C

`-(2)/(3) (d[A])/(d t)`

D

`-(3)/(2) (d[A])/(d t)`

Text Solution

Verified by Experts

The correct Answer is:
C
`-(1)/(3)(d[A])/(d t) = (1)/(2)(d[B])/(d t) :. (d[B])/(d t) = -(2)/(3) (d[A])/(d t)`
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Knowledge Check

  • 3A to 2B , rate of reaction (+d [B])/( dt) is equal to:

    A
    `- (3)/(2) (d[A])/(dt)`
    B
    `- (2)/(3) (d[A])/( dt)`
    C
    `- (1)/(3) (d[A])/( dt)`
    D
    `+2 (d [A])/(dt)`

  • 3A to 2B , rate of reaction (+d [B])/( dt) is equal to:

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    `- (3)/(2) (d[A])/(dt)`
    B
    `- (2)/(3) (d[A])/( dt)`
    C
    `- (1)/(3) (d[A])/( dt)`
    D
    `+2 (d [A])/(dt)`

  • 2A+2C rarr2B , rate of reaction (+d(B))/(dt) is equal to

    A
    `-3/2(d(A))/(dt)`
    B
    `-(d(A))/(dt)`
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