The rate of formation of `SO_(3)` in the following reaction: `2SO_(2) + O_(2) rarr 2SO_(3)` is `10 g sec^(-1)`. The rate of disappearance of `O_(2)` will be

Options

A. `5 g sec^(-1)`
B. `100g sec^(-1)`
C. `20 g sec`
D. `2 g sec^(-1)`

Answer

D

Explanation

`2SO_(2) + O_(2) rarr 2SO_(3)`
`r_(SO_(3))=10 g//sec =10/80 "mol"//sec`
Also, `r_(O_(2))/1=r_(So_(3))/2 implies r_(O_(2))=10/80 xx1/2 "mol"//sec`
`=(10/160)xx32 g//sec=2 g//sec`