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Of the ions Zn^(2), Ni^(2 +) and Cr^(3 +...

Of the ions `Zn^(2), Ni^(2 +)` and `Cr^(3 +)` [atomic number of `Zn = 30, Ni = 28, Cr = 24`]

A

Only `Ni^(2+)` is coloured and `Zn^(2+)` and `Cr^(3+)` are colourless

B

All three are colourless

C

All three are coloured

D

Only `Zn^(2+)` is colourless and `Ni^(2+)` and `Cr^(3+)` are coloured

Text Solution

Verified by Experts

The correct Answer is:
D
`Ni^(2 +)` and `Cr^(3 +)` are coloured. But `Zn^(2 +)` is colourless because of absence of unpaired `e^(-2)`
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Knowledge Check

  • Of the ions Zn^(2+),Ni^(2+) and Cr^(3+) (atomic number Zn=30,Ni=28,Cr=24):

    A
    Only `Zn^(2+)` is colourless and `Ni^(2+) and Cr^(3+)` are coloured.
    B
    all three are colourless.
    C
    all three are coloured
    D
    only `Ni^(2+)` is coloured and `Zn^(2+)` and `Cr^(3+)` are colourless.

  • Out of the ions Zn^(2+), Ni^(2+) and Cu^(3+) (At. Nos. Zn=30 Ni=28, Cr=24)

    A
    only `Zn^(2+)` is colourless and `Ni^(2+)` and `Cr^(3+)` are coloured
    B
    all three are colourless
    C
    all three are coloured
    D
    only `Ni^(2+)` is coloured and `Zn^(2+)` and `Cr^(3+)` are colourless

  • The incorrect statement(s) about Cr^(2+) and Mn^(3+) is (are) [Atomic numbers of Cr = 24 and Mn = 25]

    A
    `Cr^(2+)` is a reducing agent
    B
    `Mn^(3+)` is an oxidizing agent
    C
    Both `Cr^(2+) and Mn^(3+)` exhibit `d^(4)` electronic configuration
    D
    When `Cr^(2+)` is used as a reducing agent, the chromium ion attains `d^(5)` electronic configuration

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    Consier the following ions 1. Ni^(2+) 2. Co^(2+) 3. Cr^(2+) 4. Fe^(3+) Atomic number : Cr=24, Fe=26, Co=27, Ni=28. The correct sequence of increasing order of the number of unpaired electrons in these ions is

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    Which of the following is an inner orbital complex as well as diamagnetic in behaviour [Atomic numbers Zn = 30, Cr = 24, Co = 27, Ni = 28.]

    Which of the following complex ions is expected to absorb visible light ? [At. No. Zn = 30, Sc = 21, Ti = 22, Cr = 24]

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