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Assertion : The highest manganese fluroi...

Assertion : The highest manganese fluroide is `MnF_(4)` and the highest oxide is `Mn_(2) O_(7)`.
Reason : In `Mn_(2) O_(7)`, each `Mn` is tetrahedrally surrounded by `O's` including `Mn-O-Mn` bridge.

A

If both assetion and reason are true and the reason is the correct explanation of the assertion.

B

If both assertion and reason are ture but reason is not the correct explanation of the assertion.

C

If assertion is true but reason is false.

D

If assertion is false but reason is true.

Text Solution

Verified by Experts

The correct Answer is:
B
Both assertion and reason are correct and reason is not the correct explanation of assertion.
Manganese with fluorine form `MnF_(4)` in highest oxidation state because of high electronegatively of fluorne.
Oxygen forms multiple bonds to metals which expalin its superiority over fluorine.
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MnF_(7) is not stable while Mn_(2)O_(7) is stable.

Highest oxidation state of manganesein fluoride is +4 (MnF_(4)) but highest oxidation state in oxides is +7 ( Mn_(2)O_(7)) because "…................" .

Knowledge Check

  • Mn_(2)O_(7) is

    A
    acidic oxide
    B
    basic oxide
    C
    neutral oxide
    D
    amphoteric oxide

  • Higher oxidation state of manganese in fluoride is +4 (MnF_(4)) but highest oxidation state in oxides is +7(Mn_(2)O_(7)) because

    A
    fluorine is more electronegative than oxygen
    B
    fluorine does not posses d- orbitals.
    C
    fluorine stabilises lower oxidation state.
    D
    In covalent compounds fluorine can form single bond only while oxygen forms double bond.

  • The highest oxidation state of Mn is shown by

    A
    `K_(2)MnO_(4)`
    B
    `KMnO_(4)`
    C
    `MnO_(2)`
    D
    `Mn_(2)O_(2)`

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    (a) Give reasons for the following: (i) Mn^(3+) is a good oxidising agent. (ii) E^(@)_(M^(2+)//M) values are not regular for first row transition metals (3d series). (iii) Although 'F' is more electronegative than 'O', the highest Mn fluoride is MnF_(4) , whereas the highest oxide is Mn_(2)O_(7) . (b) Complete the following equations : (i) 2CrO_(4)^(2-)2H^(+)to (ii) KMnO_(4)overset("heat")to

    (a) Give reasons for the following : (i) Mn^(3+) is a good oxidising agent. (ii) E(M^(2+)//M)^(@) values are not regular for first row transition metals (3d series). (iii) Although 'F' is more electronegative then 'O', the highest Mn fluoride is MnF_(4) whereas the highest oxide is Mn_(2)O_(7) . Complete the following equations : (ii) 2 CrO_(4)^(2-)+2H^(+)rarr (ii) KMnO_(4)overset("heat")rarr

    Mn_(2)O_(7) is an acidic oxide, why ?

    Which compound amongst the following gas the highest oxidation number of Mn? KMnO_(4), K_(2)MnO_(2), MnO_(2) and Mn_(2)O_(3)

    The highest oxidation state shown by Mn is

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