The coordination number of Pt in `[Pt(NH_3)_4Cl_2]` ion is

Options

A. (a) `2`
B. (b) `4`
C. (c) `6`
D. (d) `8`

Answer

To determine the coordination number of platinum (Pt) in the complex ion \([Pt(NH_3)_4Cl_2]\), we follow these steps:

### Step 1: Identify the Central Metal Atom
The central metal atom in the given complex is platinum (Pt).

### Step 2: Identify the Ligands
The ligands attached to the platinum in this complex are:
- 4 ammonia molecules (\(NH_3\))
- 2 chloride ions (\(Cl^-\))

### Step 3: Determine the Type of Ligands
- Ammonia (\(NH_3\)) is a monodentate ligand, meaning it can attach to the metal at one point.
- Chloride ions (\(Cl^-\)) are also monodentate ligands.

### Step 4: Count the Number of Ligands
Now, we count the total number of ligand atoms attached to the platinum:
- From 4 ammonia molecules, we have 4 nitrogen atoms contributing to the coordination.
- From 2 chloride ions, we have 2 chlorine atoms contributing to the coordination.

### Step 5: Calculate the Coordination Number
The coordination number is the total number of ligand atoms attached to the central metal atom. Therefore, we add the contributions from both types of ligands:
- Coordination number from \(NH_3\): 4
- Coordination number from \(Cl^-\): 2

Total coordination number = \(4 + 2 = 6\)

### Conclusion
Thus, the coordination number of platinum in \([Pt(NH_3)_4Cl_2]\) is **6**.

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