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The probability that a bulb produced by a factory will fuse after 150 days of use is 0.05.
The probability that out of 5 such bulbs not more than one will fuse after 150 days of use is

A

`(5)/(5)((19)/(20))^4`

B

`(6)/(5)((19)/(20))^4`

C

`(3)/(5)((19)/(20))^4`

D

`(4)/(5)((19)/(20))^4`

Text Solution

Verified by Experts

The correct Answer is:
B
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The probability that a bulb produced by a factory will fuse after 150 days if used is 0.05. what is the probability that out of 5 such bulbs none will fuse after 150 days of use? 1-(19/20)^5 b. (19/20)^5 c. (3/4)^5 d. 90(1/4)^5

The probability that a bulb produced by a factory will fuse after 150 days is 0.05. Find the probability that out of 5 such bulbs (i) none  (ii) not more than one (iii) more than one (iv) at least one will fuse after 150 days of use.

Knowledge Check

  • The probability that a bulb produced by a factory will fuse after 150 days of use is 0.05. The probability that out of 5 such bulbs more than one will fuse after 150 days of use is

    A
    `1-((6)/(5))((19)/(20))^4`
    B
    `1-((3)/(5))((19)/(20))^4`
    C
    `1-((7)/(9))((19)/(20))^4`
    D
    `1-((2)/(5))((19)/(20))^4`
  • The probability that a bulb produced by a factory will fuse after 150 days of use is 0.05. The probability that out of 5 such bulbs at least one will fuse after 150 days of use is

    A
    `1-((19)/(20))^4`
    B
    `1-((19)/(20))^3`
    C
    `1-((19)/(20))^2`
    D
    `1-((19)/(20))^5`
  • If the probability that a randomly selected bulb produced by a factory will fuse after 200 days of use is 0.15, then in a random selection of 8 bulbs, the probability of getting not more than one bulb that will fuse after 200 days of use is -

    A
    `2.05 xx (0.85)^(7)`
    B
    `1-2.05xx(0.85)^(7)`
    C
    `(0.85)^(8)`
    D
    none of these
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