Home
Class 12
MATHS
Statement-I: General solution of the equ...

Statement-I: General solution of the equation `(tan4x - tan2x)/(1+tan4x tan2x) =1` is `x = (npi)/2 + pi/8, n int Z`
Statement-II: `tanalpha=1`, therefore general solution is `alpha= npi + pi/4, n int Z`

A

Statement-I is true, statement-II is true and Statement-II is a correct explanation for Statement-I.

B

Statement-I is true, Statement-II is true but staement-II is not a correct explanation of statement-I

C

Statement-I is true, Statement-II is false.

D

Statement-I is False, Statement-II is true.

Text Solution

Verified by Experts

The correct Answer is:
d
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GENERAL SOLUTIONS OF TRIGNOMETRIC EQUATIONS

    CHHAYA PUBLICATION|Exercise Comprehension Type|6 Videos
  • ELLIPSE

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Exams (D comprehension Type)|7 Videos
  • IDENFINITE INTEGRAL

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Examination (Comprehension Type )|6 Videos

Similar Questions

Explore conceptually related problems

int ("tan"x)/(1 + tan x )dx

int tan x tan 2x tan 3x dx

Knowledge Check

  • The general solution of the equation tan 2 theta tan theta =1 is-

    A
    `(2n +1). pi/4`
    B
    `(2n +1). (pi)/(6)`
    C
    `(2n +1). (pi)/(2)`
    D
    `(2n + 1). (pi)/(3)`
  • State which of the following is the general solution of the equation tan3x =1 ?

    A
    `npi + pi/12`
    B
    `(11pi)/4, (7pi)/2`
    C
    `(npi)/3 + pi/12`
    D
    `(npi)/3 + pi/4`
  • Similar Questions

    Explore conceptually related problems

    The number of solutions of the equation tan^(-1)(1+x)+tan^(-1)(1-x)=pi/2 is 2 (b) 3 (c) 1 (d) 0

    The number of solution of the equation tan^-1 sqrt(x(x+1)) + sin^-1sqrt(x^2 + x + 1) = pi/2

    Solve the equation tan^(-1)2x+tan^(-1)3x=pi/4

    int (tan x - tan alpha)/(tan x+tan alpha)dx

    x = npi - tan^-1 3 is a solution of the equation 12 tan 2x + sqrt10/cosx + 1 = 0 if

    If tan^-1 x + tan^-1 2x + tan^-1 3x = pi , then: