Home
Class 12
MATHS
Let f(x)=x^2+b1x+c1 andg(x)=x^2+b2x+c2. ...

Let f`(x)=x^2+b_1x+c_1` and`g(x)=x^2+b_2x+c_2`. When f(x)=0 then the real roots of f(x) are `alpha,beta` and when g(x)=0 then the real roots of g(x) are `alpha+h,beta+h`. Minimum value of f(x) is `-1/4` and when x=`7/2` then value of g(x) will be minimum.
Minimum value of g(x) is-

A

`-1/4`

B

-1

C

`-1/3`

D

`-1/2`

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • QUADRATIC EQUATIONS

    CHHAYA PUBLICATION|Exercise Sample Question for Competitive Exams (Assertion- Reason Type)|2 Videos
  • QUADRATIC EQUATIONS

    CHHAYA PUBLICATION|Exercise Sample Question for Competitive Exams (Integer Answer type)|5 Videos
  • PROPERTIES OF TRIANGLE

    CHHAYA PUBLICATION|Exercise Assertion- Reason Type:|2 Videos
  • QUESTION PAPER -2018

    CHHAYA PUBLICATION|Exercise WBJEE|45 Videos

Similar Questions

Explore conceptually related problems

Let f(x)=(1)/(1+x^(2)) and g(x) is the inverse of f(x) ,then find g(x)

Let f:R→R: f(x)=x+1 and g:R→R: g(x)=2x−3 . Find (f−g)(x) .

Knowledge Check

  • Let f (x)=x^2+b_1x+c_1 and g(x)=x^2+b_2x+c_2 . When f(x)=0 then the real roots of f(x) are alpha,beta and when g(x)=0 then the real roots of g(x) are alpha+h,beta+h . Minimum value of f(x) is 1/4 and when x= 7/2 then value of g(x) will be minimum. Value of b_2 is-

    A
    -5
    B
    9
    C
    -8
    D
    -7
  • Let f (x)=x^2+b_1x+c_1 and g(x)=x^2+b_2x+c_2 . When f(x)=0 then the real roots of f(x) are alpha,beta and when g(x)=0 then the real roots of g(x) are alpha+h,beta+h . Minimum value of f(x) is -1/4 and when x= 7/2 then value of g(x) will be minimum. Roots of g(x)=0 are-

    A
    3,-4
    B
    `-3,4`
    C
    3,4
    D
    `-3,-4`
  • The minimum value of f(x)=2x^(2)+x-1 is-

    A
    `-(1)/(4)`
    B
    `(3)/(4)`
    C
    `(9)/(4)`
    D
    `-(9)/(8)`
  • Similar Questions

    Explore conceptually related problems

    If f(x) is an invertible function and g(x)=2f(x)+5, then the value of g^(-1)(x)i s

    Let f(x)=ax^(2)+bx+c , g(x)=ax^(2)+qx+r , where a , b , c , q , r in R and a lt 0 . If alpha , beta are the roots of f(x)=0 and alpha+delta , beta+delta are the roots of g(x)=0 , then

    Let f(x)={x+1,x >0, 2-x ,xlt=0 and g(x)={x+3,x 0)g(f(x)).

    Letf(x)= x^2+b_1x+c_1 ,g(x)= x^2+b_2x+c_2 . Real roots fo f(x)=0 be alpha,beta and real roots ofg(x)=0 be alpha+delta,beta+delta .Least value of f(x) be -1/4. Least value of g(x) occurs at x=7/2 The least value of g(x) is

    Let f(x)=sin x+cosx and g(x)=x^(2)-1 , then g{f(x)} is invertible if -