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If n and m (ltn) are two positive intege...

If n and m `(ltn)` are two positive integers then `n(n-1)(n-2)...(n-m)`=

A

`(n!)/((m+n)!)`

B

`(n!)/((m-n)!)`

C

`(m!)/((m-n-1)!)`

D

`(n!)/((n-m-1)!)`

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