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.^(n-1)C(r)+^(n-1)C(r-1)=...

`.^(n-1)C_(r)+^(n-1)C_(r-1)=`

A

`.^(n)C_(r+1)`

B

`.^(n)C_(r+1)`

C

`.^(n+1)C_(r)`

D

`.^(n)C_(r)`

Text Solution

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The correct Answer is:
C
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