Home
Class 12
MATHS
We have to choose 11 players for a crick...

We have to choose 11 players for a cricket team from 8 batman , 6 bowlers , 4 all rounders and 2 wicket keepers in the following conditions .
The number of selections when almost one all rounder and one wicket keeper will play -

A

`.^(4)C_(1)xx.^(14)C_(11)+.^(2)C_(1)xx.^(14)C_(10)+.^(4)C_(1)xx.^(2)C_(1)xx.^(14)C_(9)+.^(14)C_(11)`

B

`.^(4)C_(1)xx.^(15)C_(11)+.^(15)C_(11)`

C

`.^(4)C_(1)xx.^(15)C_(10)+.^(15)C_(11)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • PERMUTATION AND COMBINATION

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Exams E Assertion -Reason Type|2 Videos

  • PERMUTATION AND COMBINATION

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Exams B (Integer Type )|5 Videos

  • PARABOLA

    CHHAYA PUBLICATION|Exercise Sample Questions for Competitive Exams ( E Assertion -Reason Type )|2 Videos

  • PLANE

    CHHAYA PUBLICATION|Exercise Sample Question for Competitive Examination( E Assertion - Reason Type )|2 Videos

Similar Questions

Explore conceptually related problems

We have to choose 11 players for a cricket team from 8 batman , 6 bowlers , 4 all rounders and 2 wicket keepers in the following conditions . Number of selections when a particular batsman and a particular wicket keeper do not want to play together -

We have to choose 11 players for a cricket team from 8 batman , 6 bowlers , 4 all rounders and 2 wicket keepers in the following conditions . Numer of selections when two particular batsmen do not want to play when a paritcular bowler will play -

The numbers 2,3,4,5 and 6 written on five pieces of paper. Theses pieces of paper are put in a bag and then mixed thoroughly. A man draws at random two pieces of paper from the bag one after the other without replacement. Describe the following events associated with this random experiment : A : the number on the first piece is less than the one on the second piece, B: the sum of the numbers on the two pieces is 8 or 9 , C: the number on the first piece is odd and D: the number on the second piece is greater than 4. Is there any pair of events which are mutually exclusive?

In how many ways can one select a cricket team of eleven from 17 players in which only 5 players can bowl if each cricket team of 11 must include exactly 4 bowlers?

Column I, Column II The number of five-digit numbers having the product o digit 20 is, p. > 70 A closest has five pairs of shoes. The number of ways in which four shoes can be drawn from it such that there will be no complete pair is, q. <60 Three ladies have each brought their one child for admission to a school. The principal wants to interview the six persons one by one subject to the condition that no mother is interviewed before her child. The number of ways in which interview can be arranged is, r. in (50 ,110) The figures 4, 5, 6, 7, 8 are written in every possible order. The number of numbers greater than 56000 is, s. in (40 ,70)

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(-13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . The wavelength of radiation emitted for the transition of the electron of He^+ ion from n=4 to n=2 is

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . Which among the following differences in the energy levels for a Li^(2+) ion is minimum ?

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . For what wavelength of incident radiation He^+ ion will be raised to fourth quantum state from ground state?

H, He^(+), Li^(2+) are examples of atoms or ions with one electron each . The energy of such atoms when in the n-th energy state (according to Bohr,s theory , n=1,2,3…. =principal quantum number ) is E_n =(-13.6 Z^2)/(n^2) eV (1 eV =1.6xx10^(-19)J) . For the ground state ,n=1 . in order to raise the atom from the ground state to n=f , the suitable incident light should have a wavelength given by lambda=(hc)/(E_f-E_1) . But the atom cannot stay permanently in the f-energy state, ultimately , it comes to the ground state by radiating the extra energy , E_f-E_1 as electromagnetic radiation . The electron of the atom comes from n=f to n=1 in one or more steps using the permitted energy levels . As a result there is a possibility of emission of radiation with more than one wavelength from the atom. Planck's constant =6.63 xx10^(-34)J*s and velocity of light c=3xx10^(8)m*s^(-1) . (i)What is the wavelength of the light incident on the atom to raise it to the fourth quantum level from ground state ?