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A circle s passes through the point ( 0,...

A circle s passes through the point ( 0,1) and is orthogonal to the circles ` ( x - 1)^(2) + y^(2) = 16` and ` x^(2) + y^(2) = 1 `. Then

A

radius of S is 8

B

radius of S is 7

C

center of S is ( -7 , 1)

D

center of s is ( - 8 , 1)

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The correct Answer is:
A, B, C, D
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Knowledge Check

  • The equation of the circle passing through the point (1 , 1) and the points of intersection of x^(2) + y^(2) - 6x - 8 = 0 and x^(2) + y^(2) - 6 = 0 is _

    A
    `x^(2) + y^(2) + 3x - 5 = 0 `
    B
    `x^(2) + y^(2) - 4x + 2 = 0 `
    C
    `x^(2) + y^(2) + 6x - 4 = 0 `
    D
    `x^(2) + y^(2) - 4y - 2 = 0 `

  • Equation of the circle which passes through the points of intersection of circles x ^(2) +y^(2) =6 and x^(2)+y^(2) -6x +8 =0 and the point (1,1) is-

    A
    `x^(2) +y^(2) -6x +4=0`
    B
    `x ^(2)+y^(2) -3x +1=0`
    C
    `x ^(2)+y^(2) -4y +2=0`
    D
    `x^(2)+y^(2) -6x -6y+10=0`

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