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The average K.E. of an ideal gas is calo...

The average K.E. of an ideal gas is calories per mole is approximately equal to

A

three times the absolute temperature

B

absolute temperature

C

two times the absolute temperature

D

1.5 times the absolute temperature

Text Solution

Verified by Experts

The correct Answer is:
A
K.E. = `(3)/(2)RT =(3)/(2)xx 2xx T= 3T`
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Knowledge Check

  • The average K.E. of an ideal gas in calories per mole is approximately equal to

    A
    Three times the absolute temperature
    B
    Absolute temperature
    C
    Two times the absolute temperature
    D
    1.5 times the absolute temperature

  • Read the paragraph carefully and answer the following questions: On the basis of the postulates of kinetic theory of gases, it is possible to derive the mathematical expression, commonly known as kinetic gas equation. PV=(1)/(3) mnU^(2) where, P = Pressure of the gas, V = Volume of the gas, m = Mass of a molecule, n = Number of molecules present in the given amount of a gas and u = Root mean square speed For one mole of gas, PV=RT and n=N_(A) (1)/(3) mN_(A)u^(2)=RT (2)/(3) cdot (1)/(2) mN_(A) u^(2)=RT ((1)/(2)mN_(A)u^(2)=" K. E. per mol") (2)/(3) K.E.=RT rArr K.E. =(3)/(2) RT Average kinetic energy per mol does not depend on the nature of the gas but depends only on temperature. Thus, when two gases are mixed at the same temperature, there will be no rise or decrease in temperature unless both react chemically. Average kinetic energy per molecule =("Average K. E. per mole")/(N) =(3)/(2) (RT)/(N) rArr (3)/(2) kT where k is the Boltzmann constant. The average K.E. of an inert gas in calories per mole is approximately equal to

    A
    three times the absolute temperature
    B
    absolute temperature
    C
    two times the absolute temperature
    D
    1.5 times the absolute temperature

  • The average pressure of an ideal gas is

    A
    `p=(1//3)mnV_(av)^(2)`
    B
    `p=(1//2)mnV_(av)`
    C
    `p=(1//4)mnV_(av)^(2)`
    D
    `p=(1//3)mnV_(av)`

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    The average kinetic energy of an ideal gas per molecule in SI units at 25^(@)C will be

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