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The average K.E. of an ideal gas is calo...

The average K.E. of an ideal gas is calories per mole is approximately equal to

A

three times the absolute temperature

B

absolute temperature

C

two times the absolute temperature

D

1.5 times the absolute temperature

Text Solution

Verified by Experts

The correct Answer is:
A
K.E. = `(3)/(2)RT =(3)/(2)xx 2xx T= 3T`
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